If the time of flight is 39 μs, the reflector depth is ____ cm and the total distance traveled is ____ cm.

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Multiple Choice

If the time of flight is 39 μs, the reflector depth is ____ cm and the total distance traveled is ____ cm.

Explanation:
The time of flight measures the pulse’s round-trip travel to the reflector and back, so the one-way depth is half the round-trip distance. In soft tissue, the speed of sound is about 1540 m/s, which is 0.154 cm per microsecond. Multiply by the time of flight to get the round-trip distance: 39 μs × 0.154 cm/μs ≈ 6.0 cm. Half of that is the reflector depth: about 3.0 cm. The total distance the pulse travels is the round-trip distance, approximately 6 cm.

The time of flight measures the pulse’s round-trip travel to the reflector and back, so the one-way depth is half the round-trip distance. In soft tissue, the speed of sound is about 1540 m/s, which is 0.154 cm per microsecond. Multiply by the time of flight to get the round-trip distance: 39 μs × 0.154 cm/μs ≈ 6.0 cm. Half of that is the reflector depth: about 3.0 cm. The total distance the pulse travels is the round-trip distance, approximately 6 cm.

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