What happens to beam diameter in the far field as frequency increases?

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Multiple Choice

What happens to beam diameter in the far field as frequency increases?

Explanation:
Diffraction governs how a beam spreads in the far field, and the amount of spread is tied to the wavelength. The far-field divergence for a circular aperture scales with λ/D, so as the wavelength gets shorter (which happens when frequency increases, since λ = c/f), the divergence shrinks. With a fixed distance, a smaller divergence angle means the beam diameter in the far field becomes smaller. In other words, increasing frequency reduces the far-field beam diameter (roughly proportionally to the change in wavelength; doubling the frequency halves the wavelength and about halves the beam spread).

Diffraction governs how a beam spreads in the far field, and the amount of spread is tied to the wavelength. The far-field divergence for a circular aperture scales with λ/D, so as the wavelength gets shorter (which happens when frequency increases, since λ = c/f), the divergence shrinks. With a fixed distance, a smaller divergence angle means the beam diameter in the far field becomes smaller. In other words, increasing frequency reduces the far-field beam diameter (roughly proportionally to the change in wavelength; doubling the frequency halves the wavelength and about halves the beam spread).

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