When the depth of view is set to 5 cm, the PRP is ______.

When the depth of view is set to 5 cm, the PRP is ______.

• A. 120 μs
• B. 30 μs
• C. 65 μs
• D. 200 μs

Answer: (C)

The key idea is how the Pulse Repetition Period (PRP) relates to imaging depth. PRP is the time between emitted ultrasound pulses, and it must be long enough for echoes from the deepest point of interest to travel to and return. That total round‑trip time is tied to depth and the speed of sound in tissue. PRP = 2 × depth / speed_of_sound With depth = 5 cm (0.05 m) and speed_of_sound ≈ 1540 m/s: PRP ≈ 2 × 0.05 / 1540 = 0.10 / 1540 ≈ 6.5 × 10^-5 s ≈ 65 μs. So the PRP is about 65 microseconds. This aligns with the given option.

The key idea is how the Pulse Repetition Period (PRP) relates to imaging depth. PRP is the time between emitted ultrasound pulses, and it must be long enough for echoes from the deepest point of interest to travel to and return. That total round‑trip time is tied to depth and the speed of sound in tissue.

PRP = 2 × depth / speed_of_sound

With depth = 5 cm (0.05 m) and speed_of_sound ≈ 1540 m/s:

PRP ≈ 2 × 0.05 / 1540 = 0.10 / 1540 ≈ 6.5 × 10^-5 s ≈ 65 μs.

So the PRP is about 65 microseconds. This aligns with the given option.